# Line slope calculator 4x+y=25

**Straight line given by points A[5; 5] and B[6; 1]**

## Calculation:

**Slope-intercept form of line:**y = -4x+25

**Canonical form of the line equation:**4x+y-25 = 0

**Parametric form of the line equation:**

x = t+5

y = -4t+5 ; t ∈ R

**Slope:**m = -4

**Slope angle of line: φ =**-75°57'50″ = -1.3258 rad

**X intercept:**x

_{0}= 6.25

**Y intercept:**y

_{0}= q = 25

**Distance line from the origin:**d

_{0}= 6.0634

**The length of the segment AB: |AB| =**4.1231

**Vector: AB =**(1; -4)

**Normal vector: n =**(4; 1)

**Midpoint of the segment AB: M =**[5.5; 3]

**Perpendicular Bisector equation:**x-4y+6.5 = 0

**Vector OA = (5; 5) ; |OA| = 7.0711**

**Vector OB = (6; 1) ; |OB| = 6.0828**

**Scalar product OA .OB = 35**

**Angle ∠ AOB = 35°32'16″ = 0.6202 rad**